(x^2-x)/3+(2x-1)/4=13/4

Solution for (x^2-x)/3+(2x-1)/4=13/4 equation:

x in (-oo:+oo)

(x^2-x)/3+(2*x-1)/4 = 13/4 // - 13/4

(x^2-x)/3+(2*x-1)/4-(13/4) = 0

(x^2-x)/3+(2*x-1)/4-13/4 = 0

(4*(x^2-x))/(3*4)+(3*(2*x-1))/(3*4)+(-13*3)/(3*4) = 0

4*(x^2-x)+3*(2*x-1)-13*3 = 0

4*x^2+2*x-39-3 = 0

4*x^2+2*x-42 = 0

4*x^2+2*x-42 = 0

2*(2*x^2+x-21) = 0

2*x^2+x-21 = 0

DELTA = 1^2-(-21*2*4)

DELTA = 169

DELTA > 0

x = (169^(1/2)-1)/(2*2) or x = (-169^(1/2)-1)/(2*2)

x = 3 or x = -7/2

2*(x+7/2)*(x-3) = 0

(2*(x+7/2)*(x-3))/(3*4) = 0

(2*(x+7/2)*(x-3))/(3*4) = 0 // * 3*4

2*(x+7/2)*(x-3) = 0

( x+7/2 )

x+7/2 = 0 // - 7/2

x = -7/2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -7/2, 3 }